how much return you expect from commodity market

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friday support was 413 for feb future
sat support was 415 for feb future
to day tentative support is 416
so you have to take your decision accordingly
dear trade jack
pivot support of copper is 418.60 for to day ,normally bulls try to stop price at pivot support first but if they fail they will try to stop it at lower support which finally come in between 415 and 416
 
date /support / value of one momentum / trailing stop loss for next day
31/01 5103 - 28 = 5075
01/02 5128 - 21 = 5107
02/02 5163 - 23 = 5140
03/02 5196 - 22 = 5174
NOW TRAILING STOP LOSS FOR LONG TRADE IN NIFTY ON 6/2 WILL BE 5174 ,WHICH WE WILL GIVE ON 6TH FEB MORNING AND THEN WE WILL JUST SHIFT OUR STOP LOSS EVERY DAY MORNING AND WE WILL NOT OPEN TRADING WINDOW DURING THE DAY TILL STOP LOSS IS NOT TRIGGERED OR WE WILL CLOSE THE TRADE IF WE WILL GET PERFECT EXIT TRADE SET UP,WHEN WE WILL COME TO KNOW IT IS A PERFECT EXIT SET UP,THEN ON 3.25 WE CAN CLOSE OUR TRADE,BUT AFTER SUCH A LONG MOMENTUM NORMALLY WE ALWAYS WAIT FOR OUR STOP LOSS TO HIT
ENTRY SYSTEM:eek:n 1st Feb pivot support was 5191,so we give buy trigger of 5191 once ,it was triggered, we were in the trade(HERE WE HAVE ENTERED IN THE TRADE APP ONE MONTH AFTER THE TRADE WAS OPENED)
what ever stop loss is moving on up side ,every day,we are locking that much profit in nifty
SO NOW ON MONDAY WE WILL LOCK 5174-5140=34X50=1700 Rs on one lot of nifty(we have considered nifty Feb future)
did i miss the entry? Ashwini sir, i could not understand the entry.. was it at the touch of the pivot point, or after resistance was broken on the upside.
missed this trade, could you please tell us at the exact time to take the next trade pls.
really dont want to miss the next trade setup

thanks
 
Now tell me what is the age of the pilot ???
The Pilot in inexperienced / very young. The plane should reach a sustainable cruising speed in about 20 minutes and then fly at constant speed.

In above case pilot is left behind by 2250 kilometers as he is not reaching the high speed till the fourth hour. The calculation is: [(2000-500)/2]+[2000-1000]+[2000-1500].

regards

Rajeev
 
The Pilot in inexperienced / very young. The plane should reach a sustainable cruising speed in about 20 minutes and then fly at constant speed.

In above case pilot is left behind by 2250 kilometers as he is not reaching the high speed till the fourth hour. The calculation is: [(2000-500)/2]+[2000-1000]+[2000-1500].

regards

Rajeev
dear rajeevji,firstly thanks for the reply.
when i was quite young,during my college days,i used to read one magazine competition master and this was the question which was asked in IAS INTERVIEW during those days,which i read from that magazine.
NOW I REQUEST YOU TO AGAIN READ MY QUESTION,FROM POST ONE TO POST FIVE AND THEN TRY TO RE-ANSWER.
BUT BEFORE ANSWERING THINK LIKE AN IAS CANDIDATE(genius cream of intellectuals)
 
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